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24=-2x^2-36x
We move all terms to the left:
24-(-2x^2-36x)=0
We get rid of parentheses
2x^2+36x+24=0
a = 2; b = 36; c = +24;
Δ = b2-4ac
Δ = 362-4·2·24
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{69}}{2*2}=\frac{-36-4\sqrt{69}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{69}}{2*2}=\frac{-36+4\sqrt{69}}{4} $
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